Also called successive approximation. a problem-solving or computational method in which a succession of approximations, each building on the one preceding, is used to achieve a desired degree of accuracy.
an instance of the use of this method.
3.
Computers.
a repetition of a statement or statements in a program.
a different version of an existing data set, software program, hardware device, etc.:
A new iteration of the data will be released next month.
The current iteration of supermarkets is in reality a bit of a pox upon our house.
But you don't need to see every iteration to know that it is happening anyway.
The latter iteration came to be known as the stein, though the two seem to be used interchangeably.
If the algorithms were successful at moving the robots closer to a target, they'd be used in the next iteration.
Click here for the latest iteration and here for technical background.
Waiting for technology to tweak better in its next iteration is foolish.
Our next iteration of designs will be aimed at addressing these problems.
Important genes usually exist in multiple copies, in case one iteration gets damaged.
But the newest iteration is that the firm is pulling strings in the market meltdown and bailout.
Its popularity prompted another iteration the following week.
Word Origin and History for iteration
n.
late 15c., from Latin iterationem (nominative iteratio) "repetition," noun of action from past participle stem of iterare "do again, repeat," from iterum "again," from PIE *i-tero-, from pronomial root *i- (see yon).
programming Repetition of a sequence of instructions. A fundamental part of many algorithms. Iteration is characterised by a set of initial conditions, an iterative step and a termination condition. A well known example of iteration in mathematics is Newton-Raphson iteration. Iteration in programs is expressed using loops, e.g. in C: new_x = n/2; do x = new_x; new_x = 0.5 * (x + n/x); while (abs(new_x-x) > epsilon); Iteration can be expressed in functional languages using recursion: solve x n = if abs(new_x-x) > epsilon then solve new_x n else new_x where new_x = 0.5 * (x + n/x) solve n/2 n (1998-04-04)